Transition metal

Electron Configuration of Seaborgium (Sg)

Quick answer

Seaborgium (Sg, Z = 106) has the electron configuration [Rn] 5f^14 6d^4 7s^2, filling 7 shells with 2, 8, 18, 32, 32, 12, 2 electrons.

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Seaborgium: every subshell, one by one

The table below unpacks [Rn] 5f^14 6d^4 7s^2 line by line, so you can watch Seaborgium's 106 electrons take their seats in order of increasing energy.

SubshellElectronsTotal so far
[Rn]086
5f14100
6d4104
7s2106

Electrons per shell (K, L, M…)

Grouped by principal quantum number instead of subshell, Seaborgium carries 2 in shell 1, 8 in shell 2, 18 in shell 3, 32 in shell 4, 32 in shell 5, 12 in shell 6, 2 in shell 7. The outermost shell holds 2 electrons — the ones that do all the bonding.

How to derive it yourself

Follow the aufbau order (1s → 2s → 2p → 3s → 3p → 4s → 3d → …), pouring 106 electrons into orbitals of capacity 2 (s), 6 (p), 10 (d) and 14 (f) until none remain. Write the filled inner shells as the nearest noble-gas core — for Seaborgium that gives [Rn] 5f^14 6d^4 7s^2.

Students also ask

How many electron shells does Seaborgium have?

Seaborgium is in period 7, so its electrons occupy 7 shells, holding 2, 8, 18, 32, 32, 12, 2 electrons respectively.

How many valence electrons does Seaborgium have?

Its outermost shell holds 2 electrons, so Seaborgium has 2 valence electrons that take part in bonding.

What is the noble-gas shorthand for Seaborgium?

The shorthand form is exactly [Rn] 5f^14 6d^4 7s^2.