Metalloid

Electron Configuration of Boron (B)

Quick answer

Boron (B, Z = 5) has the electron configuration [He] 2s^2 2p^1, filling 2 shells with 2, 3 electrons.

Teachers call it "one fact, fully handled" — exactly what this page does for Boron. The answer sits at the top in bold; scroll for the working, the shell-by-shell breakdown and the two questions students ask most. Need the whole picture instead — history, characteristics, uses, exam questions? The full Boron page is one click away.

Boron: every subshell, one by one

Start from 1s and follow the running total: this is exactly how examiners expect you to build Boron's configuration on paper.

SubshellElectronsTotal so far
[He]02
2s24
2p15

Electrons per shell (K, L, M…)

Grouped by principal quantum number instead of subshell, Boron carries 2 in shell 1, 3 in shell 2. The outermost shell holds 3 electrons — the ones that do all the bonding.

How to derive it yourself

Follow the aufbau order (1s → 2s → 2p → 3s → 3p → 4s → 3d → …), pouring 5 electrons into orbitals of capacity 2 (s), 6 (p), 10 (d) and 14 (f) until none remain. Write the filled inner shells as the nearest noble-gas core — for Boron that gives [He] 2s^2 2p^1.

Students also ask

How many electron shells does Boron have?

Boron is in period 2, so its electrons occupy 2 shells, holding 2, 3 electrons respectively.

How many valence electrons does Boron have?

Its outermost shell holds 3 electrons, so Boron has 3 valence electrons that take part in bonding.

What is the noble-gas shorthand for Boron?

The shorthand form is exactly [He] 2s^2 2p^1.