Noble gas

Electron Configuration of Oganesson (Og)

Quick answer

Oganesson (Og, Z = 118) has the electron configuration [Rn] 5f^14 6d^10 7s^2 7p^6, filling 7 shells with 2, 8, 18, 32, 32, 18, 8 electrons.

This is the fast lane: one page, one fact, zero digressions. Read the quick answer, check the table, and if your exam needs the full derivation, the sections below walk through it step by step — in Bangla and English, like every page here. Need the whole picture instead — history, characteristics, uses, exam questions? The full Oganesson page is one click away.

Oganesson: every subshell, one by one

The table below unpacks [Rn] 5f^14 6d^10 7s^2 7p^6 line by line, so you can watch Oganesson's 118 electrons take their seats in order of increasing energy.

SubshellElectronsTotal so far
[Rn]086
5f14100
6d10110
7s2112
7p6118

Electrons per shell (K, L, M…)

Grouped by principal quantum number instead of subshell, Oganesson carries 2 in shell 1, 8 in shell 2, 18 in shell 3, 32 in shell 4, 32 in shell 5, 18 in shell 6, 8 in shell 7. The outermost shell holds 8 electrons — the ones that do all the bonding.

How to derive it yourself

Follow the aufbau order (1s → 2s → 2p → 3s → 3p → 4s → 3d → …), pouring 118 electrons into orbitals of capacity 2 (s), 6 (p), 10 (d) and 14 (f) until none remain. Write the filled inner shells as the nearest noble-gas core — for Oganesson that gives [Rn] 5f^14 6d^10 7s^2 7p^6.

Students also ask

How many electron shells does Oganesson have?

Oganesson is in period 7, so its electrons occupy 7 shells, holding 2, 8, 18, 32, 32, 18, 8 electrons respectively.

How many valence electrons does Oganesson have?

Its outermost shell holds 8 electrons, so Oganesson has 8 valence electrons that take part in bonding.

What is the noble-gas shorthand for Oganesson?

The shorthand form is exactly [Rn] 5f^14 6d^10 7s^2 7p^6.